PLEASE HELP ME FINDING ANGLE ACB AND SEND YOUR PAYTM ID SO I WILL SEND YOU 20 RUPPES FOR IT TELL ME
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140°because its a central angle
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Step-by-step explanation:
Step-by-step explanation:
∠ADC = 1/2 ∠AOC (Angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle)
∠ADC = 1/2 × 140°
∠ADC = 70°
∠ABC + 70° = 180°( Opposite sides of a Cyclic quadrilateral are supplementary)
∠ABC = 180° -70°
⇒∠ABC = 110°
Join DB such that ADBC is divided into two triangles and ∠A and ∠B is bisected
So in ΔDBC
∠C + ∠CDB + ∠DBC = 180°(Angle Sum Property)
∠C + 70° + 55° = 180°
∠C = 180° - 125°
∠C = 55°
Hope this will help you
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