Question

please help me for solving this...

Answer 1

p(x) = $x^{2} - x - 12$
From the graph:
x =4 and x = -3 are the two zeroes. (See the graph  attached)

p(x) = $x^{2} - x - 12$ = (x +3)(x - 4)
Therefore, the zeroes are 4 and -3.