Question

please help me
for these question​

Answer 1

$\large\underline{\sf{Solution-}}$

Given that,

Length of garden = 20 m

Diameter of semi - circular ends = 7 m

So, radius of semicircle, r = 3.5 m

So, Length of rectangle = 20 - 2r = 20 - 7 = 13 m

Breadth of rectangle = 7 m

Now Consider,

$\rm \: Area_{(garden)}$

$\rm \: = \: Area_{(rectangle)} + 2 \times Area_{(semi-circle)}$

$\rm \: = \: Length \times Breadth + 2 \times \dfrac{1}{2} \: \pi \: {r}^{2}$

$\rm \: = \: 13 \times 7 + \: \frac{22}{7} \: \times {(3.5)}^{2}$

$\rm \: = \: 91 + \: \frac{22}{7} \: \times \frac{7}{2} \times \frac{7}{2}$

$\rm \: = \: 91 + \: \frac{77}{2} \:$

$\rm \: = \: 91 + \: 38.5 \:$

$\rm \: = \: 129.5 \: {m}^{2}$

$\color{green}\rm\implies \:\boxed{ \rm{ \:\rm \: Area_{(garden)} = 129.5 \: {m}^{2} \: \: }}$

Now,

$\rm \: Perimeter_{(garden)}$

$\rm \: = \: 2 \times Length_{(rectangle)} + 2 \times Perimeter_{(semi-circle)}$

$\rm \: = \: 2 ( Length_{(rectangle)} +Perimeter_{(semi-circle)})$

$\rm \: = \: 2\bigg(13 + \dfrac{22}{7} \times \dfrac{7}{2} \bigg)$

$\rm \: = \: 2\bigg(13 + 11 \bigg)$

$\rm \: = \: 2 \times 24$

$\rm \: = \: 48 \: m$

$\color{green}\rm\implies \:\boxed{ \rm{ \:\rm \: Perimeter_{(garden)} \: = \: 48 \: m \: \: }}$

$\rule{190pt}{2pt}$

Additional Information :-

$\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}$

Answer 2

refer the given attachments