Question

please help me for this question?​

Answer 1

Answer:

Principal= 20000, Rate = 15%,

time(n) = 3years

Compound interest = p[1 - (R/100)]power of n

= 20000 [ 1 + (15/100)]³

= 20000[ (100 + 15)100]³

= 20000 (115/100)³

= 20000 ( 23/20)³

= 20000 × 12167/ 800

= 200 × 12167 / 8

= 25 × 12167

Compound interest = 304175

Now,

Amount = principal + interest

= 20000 + 304175

Amount = 324175 Rupees

Answer 2

SOLUTION:-

Given:

• Principal,[P]= Rs.20000
• Rate,[R]= 15%
• Time,[n]= 3 years.

To find:

The amount of compound Interest.

Explanation:

Using formula of Compound Interest:

C.I.= Amount - Principal

Or

$A = P(1 + \frac{R}{100} ) {}^{n} \\ \\ A = 20000(1 + \frac{15}{100} ) {}^{3} \\ \\ A = 20000(1 + \frac{3}{20} ) {}^{3} \\ \\ A = 20000 \times ( \frac{20+3 }{20} ) {}^{3} \\ \\ A = 20000 \times (\frac{23}{20} ) {}^{3} \\ \\ A = 20000 \times \frac{23}{20} \times \frac{23}{20} \times \frac{23}{20} \\ \\ A = 20 \times \frac{23 \times 23 \times 23}{8} \\ \\ A = Rs.\frac{243340}{8} \\ \\ A = Rs.30417.5$

Thus,

The amount is Rs.30417.5 of compound Interest.