Question

please help me friends​

Answer 1

Answer:

in step 2 or line 3 I've done inversing both the sides.......

if this is correct then thank me plzz

Answer 2

Answer:

$\frac{1}{x + 1} + \frac{2}{x - 2} = 1 \\ \frac{x - 2 + 2x + 2}{(x + 1)(x - 2)} = 1 \\ \frac{x - 2 + 2x + 2}{x( x - 2) + 1(x - 2)} = 1 \\ \frac{3x}{ {x}^{2} - 2x + x - 2 } = 1 \\ \frac{3x}{ {x}^{2} - x - 2 } = 1 \\ {x }^{2} - x - 2 = 3x \\ {x }^{2} - 3x - x - 2 = 0 \\ {x}^{2} - 4x - 2 = 0 \\ x = 2 - \sqrt{6} or \: x \: = 2 + \sqrt{6}$

hope it will help you

Plz plz mark as brainliest!!!