Question

Please Help me friends its urgent
Question) Find the equivalent resistance between A and B
i have provided the diagram too... kindly solve it fast and accurately... also i'll mark your answer brainliest...​

Answer 1

Answer:

$\green{ \therefore R_{AB} = 2\Omega}$

Explanation:

• We can remove resistance R5 due to wheatstone bridge.

$\bold{Using \: wheatstone \: theorem} \\ \implies \frac{ R_{1}}{ R_{4} } = \frac{ R_{2} }{ R_{3}} \\ \\ \implies \frac{2}{2} = \frac{2}{2} \\ \\ \tt: \implies 1 : 1$

$\bold{For \: series \: combination} \\ \implies R_{equivalent} = R_{3} + R_{4} \\ \\ \implies R_{equivalent} =2+ 2 \\ \\ \implies R_{equivalent} =4\Omega = R_{7} \\ \\ \bold{For \: series \: combination} \\ \implies R_{equivalent} = R_{1} + R_{2} \\ \\ \implies R_{equivalent} =2 + 2 \\ \\ \implies R_{equivalent} =4\Omega = R_{6} \\ \\ \bold{For \: parallel \: combination} \\ \implies \frac{1}{ R_{AB} } = \frac{1}{ R_{6}} + \frac{1}{ R_{7}} \\ \\ \implies \frac{1}{ R_{AB} } = \frac{1}{4} + \frac{1}{4} \\ \\ \implies \frac{1}{ R_{AB} } = \frac{1 + 1}{4} \\ \\ \green{\implies R_{AB} = 2 \Omega}$

Answer 2

Answer:

oo it's urgent to you to know the answer