Question

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Answer 1

Both solutions are here

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Answer 2

Answer:

MARK AS BRAINLIEST

Step-by-step explanation:

cosec^2 theta (1-cos^2theta)=x

=> x= cosec^2theta × sin^2theta

==> x= 1/sin^2 theta × sin^2 theta

=> x=. 1 answer

4.>. given angle C=90°

=> ∆ABC is a right angle at C

TO PROVE = cosec^2A-tan^2B=1

cosec^2A= (AB/BC)^2

tan^2B= (AC/BC)^2

=> cosec^2A-tan^2B= (AB/BC)^2-(AC/BC)^2

LCM = (BC)^2

=>(AB)^2-(AC)2/(BC)^2

=> (BC)^2/(BC)^2= 1

PROVED