Question

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Answer 1

Answer:

Here is your answer hope it helps......

Step-by-step explanation:

In ∆AOB & ∆DOC

AO=OD ( O is mid point of AD)

<AOB=<DOC (Vertically opposite angles)

<OAB=<ODC (corresponding angles)

thus ∆AOB~=∆DOC( BY ASA) (HENCE PROVED)

Also, BO= OC (By C.P.C.T ). .......(1)

=> O IS THE MID POINT OF BC ( FROM (1) )

Answer 2

Answer:

it is given that AB is parallel to CD

angleA=angleD

angleB=angleC

OA=OD

hence triangles are congurent by ASA rule

OB=OC (by c.p.c.t.)