Question

please help me friends will mark brainliest​

Answer 1

Answer:

HERE IS UR ANSWR....!!!

Step-by-step explanation:

(i) The rate of interest = 8 %

(ii) Final amount after 3/2 years = 14061 rupee (Approx)

Step-by-step explanation:

Since, An amount P is deposited in annual rate of r (in decimals) for t years and compounded half years.

Then after t years the final amount is,

A = P(1+\frac{r}{2})^{2t}

(i) Here, After 1 year,

A = 13,000

t = 1/2 years

P= 12,500

Thus, 12500(1+\frac{r}{2})^{1}=13,000

125(1+\frac{r}{2})^{1}=130

25(1+\frac{r}{2})^{1}=26

(1+\frac{r}{2})^{1}=1.04

\frac{r}{2}=0.04

r=0.08

Thus, the annual rate = 0.08 = 8%

(ii) Now, P = 125,000

t = 1½ years = 3/2 years

r = 8%

Thus, A = 12500(1+\frac{0.08}{2})^{2\times \frac{3}{2}}

A = 12500(1+\frac{0.08}{2})^{3}

A = 12500\times 1.124864=14060.8\approx 14061

HOPE IT HELP$..!!!!

Answer 2

Step-by-step explanation:

(i) The rate of interest = 8 %

(ii) Final amount after 3/2 years = 14061 rupee (Approx)

Step-by-step explanation:

Since, An amount P is deposited in annual rate of r (in decimals) for t years and compounded half years.

Then after t years the final amount is,

A = P(1+\frac{r}{2})^{2t}

(i) Here, After 1 year,

A = 13,000

t = 1/2 years

P= 12,500

Thus, 12500(1+\frac{r}{2})^{1}=13,000

125(1+\frac{r}{2})^{1}=130

25(1+\frac{r}{2})^{1}=26

(1+\frac{r}{2})^{1}=1.04

\frac{r}{2}=0.04

r=0.08

Thus, the annual rate = 0.08 = 8%

(ii) Now, P = 125,000

t = 1½ years = 3/2 years

r = 8%

Thus, A = 12500(1+\frac{0.08}{2})^{2\times \frac{3}{2}}

A = 12500(1+\frac{0.08}{2})^{3}

A = 12500\times 1.124864=14060.8\approx 14061