Question

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Answer 1

Answer:

6) BC = 8 cm

7) length = 12 cm

Step-by-step explanation:

6) perimeter of ABCD = 36 cm

AD = BC

DC = AB

AB = 10 cm (given)

therefore DC = 10 cm

perimeter of ABCD = AB + BC + CD + DA 36 = 10+BC+10+AD

36 = 20+BC+BC (BC = AD)

2*BC = 36-20

BC = 16/2

BC = 8 cm

7)

perimeter of rectangle = 2(length+breadth)

38 = 2(length+7)

38/2 = length+7

19 = length+7

length = 19-7

length = 12 cm

Answer 2

Question:

1. Perimeter of ABCD is 36 cm, length is 10 cm. Find BC.

2. Perimeter of ABCD is 38 cm, it's breadth is 7 cm. Find the length.

Answer:

$1. Breadth \: of \: rectangle \: is \: \underline{ \sf \pink{ \bf8 \: cm}}$

$2. Length \: of \: rectangle \: is \: \underline{ \sf \pink{ \bf12 \: cm}}$

Step-by-step explanation:

Solution for ${1}^{st}$ Question;

ABCD is a rectangle,

To find:

$Breadth \: of \: rectangle = ?$

Given:

$\star Perimeter \: of \: rectangle = 36cm$

$\star Length \: of \: rectangle = 10cm$

We know that,

$\boxed{Perimeter \: of \: rectangle = 2(l + b)}$

$\implies 36 = 2(10 + b)$

$\implies 36 = 20 + 2b$

$\implies 2b = 16$

$\implies \boxed{b =8cm}$

$\therefore Breadth \: of \: rectangle \: is \: \underline{\bf 8 \: cm}$

_______________________________________

Solution for ${2}^{nd}$ Question;

ABCD is a rectangle,

To find:

$Length \: of \: rectangle =?$

Given:

$\star Perimeter \: of \: rectangle = 38cm$

$\star Breadth \: of \: rectangle = 7cm$

We know that,

$\boxed{Perimeter \: of \: rectangle = 2(l + b)}$

$\longmapsto 38 = 2(l + 7)$

$\longmapsto 38 = 2l + 14$

$\longmapsto 2l = 24$

$\longmapsto \boxed{l = 12cm}$

$\therefore Length \: of \: rectangle \: is \: \underline{\bf 12 \: cm}$_______________________________________

More information:

$Area\:of\: rectangle=l \times b$

★ It has four vertices and four corners.

★ It's internal angle is 90° .