Question

please help me guys​

Answer 1

Answer:

Step-by-step explanation:

3cotθ=2

cotθ=2/3=base/height

So let base 2x,height=3x

so hypotenuse=√4x²+9x³=√13x²=x√13

sin θ=3x/x√13=3/√13

cosθ=2x/x√13=2/√13

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now

(4sinθ-3cosθ)/2sinθ+6cosθ

First numerator

N=4sinθ-3cosθ=4*3/√13-3*2/√13

N=1/√13 ( 12-6)=6/√13

Denominator

D=2sinθ + 6cosθ

=2*3/√13+6*2/√13

=1/√13(6+12)=18/√13

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Hence (4sinθ-3cosθ) / (2sinθ+6cosθ)

=6/√13 /18/√13

=6/18

=1/3=RHS