Question

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Answer 1

Answer:

in this way u can solve this question. this is the formula.

Step-by-step explanation:

this helps you

Answer 2

Answer:

Question:-

2 years ago Samantha deposited Rs. 1,600 in a bank. At the end of the period she earned Rs.192 as interest. Find the rate of interest ?

Given:-

2 years ago Samantha deposited ₹1600.At the end of the period she earned ₹192 as interest

To find:-

The rate of interest

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So here it is given that,

Principal(p) =₹1600

Rate of interest(r) =?

Time(n) =2 years

Interest=₹192

$S. I= \frac{p \times r \times t}{100}$

Time which can be also expressed as t

By substituting the given values we get,

$192 = \frac{1600 \times r \times 2}{100}$

So we already know the interest that's why we are using this to substitute

$\mapsto \: 192 = \frac{3200 \times r}{100}$

$\mapsto \: \frac{192 \times 100}{3200} = r$

$\mapsto \: \frac{19200}{3200} = r$

By cancelling with 3200 we get,

$\mapsto \: \frac{6}{1} = r$

$6 = r$

Therefore the rate of interest is 6%

Step-by-step explanation:

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