please help me guys.....
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13)(I)<BDA=<BEA=90°
BA=BA
AD=BE since altitudes of equilateral triangle are equal
hence from SSA criteria ∆ADB=∆ABE
Thus,AD=BE by CPCT
(ii)in equilateral triangles Altitudes are themselves are medians SO altitudes divide the opposite sides into 2equal parts
hence BD=CE
14)(I) given that AO=BO
OC=OD
and <AOD=<BOC vertically opposite angles
by SSA criteria ∆AOD=∆BOC
(ii) since ∆AOD=∆BOC
AD=BC by CPCT
(iii)since ∆AOD=∆BOC
<ADB=<ACB by CPCT
BA=BA
AD=BE since altitudes of equilateral triangle are equal
hence from SSA criteria ∆ADB=∆ABE
Thus,AD=BE by CPCT
(ii)in equilateral triangles Altitudes are themselves are medians SO altitudes divide the opposite sides into 2equal parts
hence BD=CE
14)(I) given that AO=BO
OC=OD
and <AOD=<BOC vertically opposite angles
by SSA criteria ∆AOD=∆BOC
(ii) since ∆AOD=∆BOC
AD=BC by CPCT
(iii)since ∆AOD=∆BOC
<ADB=<ACB by CPCT
queen5549:
hii
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