Physics, asked by mukeshambani59, 1 year ago

Please help me guys.......

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Answered by immortalrohan

$\huge\mathfrak\red{HELLO}$

$<b><l>$ LET THE MASS OF ICE BE =m

MASS OF COPPER VESSEL=100g

MASS OF WATER =150g, SPECIFIC HEAT CAPACITY OF WATER = 4.2 j/g°c, SPECIFIC LATENT HEAT OF FUSION OF ICE = 336j/g

INITIAL TEMPERATURE= 50°c

FINAL TEMPERATURE =5°c

NOW WE HAVE
CHANGE IN TEMPERATURE( θ ) = 50-5= 45
HEAT LOST BY WATER=Mcθ
=150×4.2×45=28350j

HEAT LOST BY CLAORIMETER = Mcθ
=100×0.4×45= 1800j

TOTAL HEAT LOST BY CALORIMETER AND WATER = (28350+1800)j = 30150j

CHANGE IN TEMPERATURE = 5-0=5°c
HEAT GAINED BY ICE =ml+mcθ
=m(l+cθ)
=m(336+4.2×5)
= m×357

ACCORDING TO PRINCIPLE OF CALORIMETRY:
HEAT GAINED BY ICE = HEAT LOST BY WATER AND CALORIMETRY
m× 357= 30150
m= 30150 / 357= 84.45g

thus ice needed = 84.45 g

$<html><head><title></title></head><body><marquee>✨HOPE HELPFUL ✨</marquee></body><html>$

mukeshambani59: thank u

mukeshambani59: it's correct

immortalrohan: welcome

immortalrohan: brother

immortalrohan: hi

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