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the answer is 2root3
#hope it help uh.
BRAINLIEST PLS
the answer is 2root3
#hope it help uh.
BRAINLIEST PLS
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Consider the following expression. tan(θ)−cot(90−θ)+sec(θ)cosec(90−θ)+sin235+sin255tan10 tan20 tan40 tan70 tan80Note that, cot(90−θ)= tan(θ) and cosec(90−θ)=sec(θ)Also, the trigonometric values tan10 and tan20 can be expressed as, tan10=tan(90−80) =cot 80 and tan20=tan(90−70) =cot 70 The value of sin235+sin255 can be determined as, sin235+sin255=sin2(90−55)+sin255 =cos255+sin255 ( since sin(90−θ)=cos(θ) )
imperialxak47:
thx
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