Question

Please help me guys


An open cone has a circular base of radius 10 cm and a slant height of 20 cm. Draw the net of the cone and label it's dimensions.

Answer 1

Answer:

Hey mate here is your answer.

Given,

Given, radius, r = 10 cm

Given, radius, r = 10 cm slant height, l = 30 cm

Given, radius, r = 10 cm slant height, l = 30 cmNow,

Given, radius, r = 10 cm slant height, l = 30 cmNow, surface area of cone= πr (r+l)

Given, radius, r = 10 cm slant height, l = 30 cmNow, surface area of cone= πr (r+l) = 3.14 x 10 ( 10 + 30 )

Given, radius, r = 10 cm slant height, l = 30 cmNow, surface area of cone= πr (r+l) = 3.14 x 10 ( 10 + 30 ) = 31.4 x 40

Given, radius, r = 10 cm slant height, l = 30 cmNow, surface area of cone= πr (r+l) = 3.14 x 10 ( 10 + 30 ) = 31.4 x 40 = 1256

Given, radius, r = 10 cm slant height, l = 30 cmNow, surface area of cone= πr (r+l) = 3.14 x 10 ( 10 + 30 ) = 31.4 x 40 = 1256 So the surface area of the cone is 1256 cm sq.

Answer 2

Given, radius, r = 10 cm slant height, l = 30 cm. Now, surface area of cone= πr (r+l) = 3.14 x 10 ( 10 + 30 ) = 31.4 x 40 = 1256. So the surface area of the cone is 1256 cm sq.

thnxx for free points