Question

please help me guys bro sis anyone ​

Answer 1

Answer:

AB||ED

BC||EF

SUM PF PARALLEL LINES = 180°

SO, PARALLEL LINES = (AB+BC)+(ED+EF)

180°

Step-by-step explanation:

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Answer 2

GIVEN :

BA || ED and BC || EF

TO PROVE :

To show, ∠ABC + ∠DEF = 180°

CONSTRUCTION :

: $\implies$ Extend E Dept ED || AB

so EP || AB

PROOF :

∠1 = ∠2 (i) ( CORRESPONDING ANGELES AS ED||AB )

∠2 + ∠DEF = 180° (ii) ( Co - interior Angle are supplementry as FF ||BC)

From (i) and (ii)

∠1 + ∠DEF = 180°

But ∠1 = ∠ABC

∠A+BC ∠DEF = 180°

hence, proved :)