Question

please help me guys it's very important for me​

Answer 1

Required Answer:-

Given:

• x² - 13x + 30 =

To find:

• αβ where α and β are the roots of the given equation.

Solution:

We know that,

➡ Product of zeroes = c/a

Here,

1. a = 1 (coefficient of x²)
2. b = -13 (coefficient of x)
3. c = 30 (coefficient of x⁰)

So,

➡ αβ = 30/1

➡ αβ = 30

★ Hence, the product of zeroes is 30

If you don't know this formula, do in this way, ↓

➡ x² - 13x + 30 = 0

➡ x² - 3x - 10x + 30 = 0

➡ x(x - 3) - 10(x - 3) = 0

➡ (x - 10)(x - 3) = 0

Therefore, either (x - 10) = 0 or (x - 3) = 0

➡ x = 10, 3

➡ Hence, the roots are 10 and 3.

★ Product of zeros (αβ) = 10 × 3 = 30

Answer:

• αβ = 30

Answer 2

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Required Answer:-

Given:

x² - 13x + 30 =

To find:

αB where α and β are the roots of the given equation.

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We know that,

↪ Product of zeroes = c/a

Here,

a = 1 (coefficient of x²)

b = -13 (coefficient of x)

c = 30 (coefficient of x⁰)

So,

↪αB = 30/1

↪ αB= 30

✒Hence, the product of zeroes is 30

If you don't know this formula, do in this way, ↓

↪ x² - 13x + 30 = 0

↪ x² - 3x - 10x + 30 = 0

↪x(x - 3) - 10(x - 3) = 0

↪(x - 10)(x - 3) = 0

Therefore, either (x - 10) = 0 or (x - 3) = 0

↪ x = 10, 3

↪ Hence, the roots are 10 and 3.

↪Product of zeros (αB) = 10 × 3 = 30

The Answer is αB = 30