Math, asked by sanjeevyadav38470, 9 hours ago

Please help me, how to solve the following question:
XY(X+Y)=30
YZ(Y+Z)=84
XZ(X+Z)=48

Ans: x=2, y=3, z=4.​

Answers

Answered by srinuvasaraoveadulap
0

Answer:

xy(x+y) =30

2* 3 (2+3)=30 6(5)=30 30=30 YZ(Y+Z) =84 3*4(3+4)=84 12(7)=84 84=84 XZ(X+Z) =48 2*4(2+4)=48 8(6)= 48 48=48

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