Question

Please help me i am asking for 6 hrs but noone is answering

Answer 1

Hey there,

Part 1-

=>√6/(√2+√3)=√6(√2-√3)/(2-3)

=-√6(√2-√3) =√18-√12

=3√2-2√3. (by rationalising) ( I ).

Part 2-

=>√3.√2/(√6+√3)=√6/(√6+√3)

=√6(√6-√3)/(6-3)=√6(√6-√3)/3

=(6-3√2)/3

=2-√2. (II)

Part 3-

=>4√3/(√6+√2)=4√3(√6-√2)/4

=√18-√6

=3√2-√6 ..(III)

A/q, (I)+(II)-(III)

=>(3√2-2√3)+(2-√2)-(3√2-√6)

=3√2- 2√3+ 2- √2- 3√2+√6

=(2-√2)-(2√3-√6)

=√2(√2-1)-√6(√2-1)

=(√2-√6)(√2-1)

Hope it helps