Question

please help me i am not able to solve​

Answer 1

Answer:

6 should be your answer

Step-by-step explanation:

I hope this was helpful!!! :)

Answer 2

$\underline{\boxed{\bold{\bigstar \; Question \; \bigstar}}}$  

➠  $\bold { Value \; of \; z \; if, \; x-\dfrac{2z}{3} + \dfrac{z}{2} = 5 }$

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$\underline{\boxed{\bold{\bigstar \; Important\;Information \; \bigstar}}}$  

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❏ Basic method to solve this type of equality is to make the variable term separate or isolate and tem solve this question.

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❏ While performing algebraic operations on fraction , one so check whether the denominator of fraction are same or not.

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❏ If not then by taking LCM one should make them same and then perform algebraic operations !

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$\underline{\boxed{\bold{\bigstar \; Answer \; \bigstar}}}$

Let's Start !

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Let's take L.C.M first and them proceed !

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$\bold { \blue { :\implies x-\dfrac{2z}{3} + \dfrac{z}{2} = 5 } }$

$\bold { \orange { :\implies \dfrac{6z}{6}-\dfrac{2\times 2z}{2\times 3} + \dfrac{3\times z}{3\times 2} = 5 } }$

$\bold { \blue { :\implies \dfrac{6z}{6} -\dfrac{4z}{6} + \dfrac{3z}{6} = 5 } }$

$\bold { \orange { :\implies \dfrac{6z-4z+3z}{6} = 5 } }$

$\bold { \blue { :\implies \dfrac{5z}{6} = 5 } }$

$\bold { \pink { :\leadsto \; z = 6 } }$

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$\boxed{\boxed{\bold{\therefore Value\;of\;z = 6}}}$

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Hope this helps u.../

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