Question

please help me I am so confused​

Answer 1

Right angle triangle

Sec A = Sqrt 2
I/cos A = sqrt 2

Cos A = 1/ sqrt 2
Therefore;


Sin A = 1/sqrt 2


It’s a 45-45-90 triangle

Answer 2

Answer:

$\frac{1}{\sqrt{2} }$

Step-by-step explanation:

Here,

sec A = $\sqrt{2}$

or,

$\frac{1}{cosA}$ = $\sqrt{2}$

cos A = $\frac{1}{\sqrt{2} }$

⇒ cos A = cos π/4

A = π/4

Now,

sin A = sin π/4

         = $\frac{1}{\sqrt{2} }$