Please help me. I'll mark as Brainliest and 50 points
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Hey mate!
Here's your answer!!
✮Kindly refer to the given attachment✮
✌ ✌ ✌
#BE BRAINLY
Here's your answer!!
✮Kindly refer to the given attachment✮
✌ ✌ ✌
#BE BRAINLY
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Let's solve in different points by considering smaller units
Cos2a + Cos2b = 2Cos(a+b)Cos(a-b)
=2Cos(270-c)Cos(a-b)
= -2Sin(c)Cos(a-b)
Cos2c = 1- 2Sin22c
4SinaSinbSinc = 2(2SinaSinb)Sinc
= 2[Cos(a-b) - Cos(a+b)]Sinc
= 2[Cos(a-b) - Cos(270-c)]Sinc
= 2[cos(a-b) + Sinc]Sinc
= 2Cos(a-b)Sinc + 2Sin2c
now add the results of these three parts and get the desired
ANS = 1
Cos2a + Cos2b = 2Cos(a+b)Cos(a-b)
=2Cos(270-c)Cos(a-b)
= -2Sin(c)Cos(a-b)
Cos2c = 1- 2Sin22c
4SinaSinbSinc = 2(2SinaSinb)Sinc
= 2[Cos(a-b) - Cos(a+b)]Sinc
= 2[Cos(a-b) - Cos(270-c)]Sinc
= 2[cos(a-b) + Sinc]Sinc
= 2Cos(a-b)Sinc + 2Sin2c
now add the results of these three parts and get the desired
ANS = 1
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