Question

please help me I need​

Answer 1

Answer:

here,

in cosBx. (Bx =angle)

there is no dimensions for angle ,

Bx=angle

x=[L/T]

B=[T/L]

similarly for D

Dt=angle

D=[1/T]

hence,D/B=[1/T]/[T/L]

D/B=[L/T²]

I.e,D/B=[LT^-2]