Question

please help me i need the answer ​

Answer 1

Step-by-step explanation:

In ∆ABC

50°+60°+Angle ACB = 180° ( sum of angle of ∆ )

Angle ACB = 180°- (50°+60°)

= 70°

Now angle CBD + 60° = 180°

angle CBD = 180°-69° = 120°

and angle CBO = 60° ( BO is bisector of angle CBO)

Similarly angle BCO = 55°

Angle 1 + Angle 2 + angle BOC = 180°

Angle 1 + Angle 2 + angle BOC = 180° ( angle sum property)

angle BOC = 180° -(55°+60°)

angle BOC = 180°- 115°

BOC = 180°- 115° = 65°