please help me i need the answer
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Step-by-step explanation:
In ∆ABC
50°+60°+Angle ACB = 180° ( sum of angle of ∆ )
Angle ACB = 180°- (50°+60°)
= 70°
Now angle CBD + 60° = 180°
angle CBD = 180°-69° = 120°
and angle CBO = 60° ( BO is bisector of angle CBO)
Similarly angle BCO = 55°
Angle 1 + Angle 2 + angle BOC = 180°
Angle 1 + Angle 2 + angle BOC = 180° ( angle sum property)
angle BOC = 180° -(55°+60°)
angle BOC = 180°- 115°
BOC = 180°- 115° = 65°
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