Question

please help me........

i will be mark as brainliest....✔

Answer 1

By Remainder Theorem,

3x - 1 = 0

$x = \frac{1}{3}$


×××××××××××

r = 9x³ - 3x² + 14x - 3

$r =$
$r = 9 \times ( { \frac{1}{3} })^{3} - 3 \times {( \frac{1}{3} })^{2} + 14( \frac{1}{3} ) - 3 \\ \\r = 9( \frac{1}{27} ) - 3( \frac{1}{9} ) + \frac{14}{3} - 3 \\ \\ r = \frac{1}{3} - \frac{1}{3} + \frac{14}{3} - 3 \\ \\ r = \frac{14}{3} - 3 \\ \\ r = \frac{14 - 9}{3} \\ \\ r = \frac{5}{3}$


Remainder is 5/3




I hope this will help you

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Answer 2

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