Question

please help me i will mark you as brainliest
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Answer 1

Answer:

45°, 90°, 45°

Step-by-step explanation:

if <POC=135° then<QOC=180-135=45°

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• • <POE=<QOC=45°..............

the line OD is perpendicular to the line PQ

so,<OQD=90°

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• • <DOC=<DOQ - <QOC =90°-45°=45°.........

the line segments E and C equally bisects with the line PQ.

so,<EOD = <DOC = 45°

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• • <EOC=<EOD+ <DOC=45+45=90°..........