Question

please help me I will mark you as brainlist ⭐⭐⭐ maa kasam but please answer correctly​

Answer 1

Question 7)

→ Given That, Cost of 1 Litre Petrol is = Rs. 42(4/7) = 298/7.

So,

→ Cost of 10(1/2) or , (21/2) Litre Petrol is = (298/7) * (21/2)

{ 298 is a multiple of 2, and 21 is a multiple of 7}.

So,

→ [ (2*149) / 7 ] * [ (3*7) / 2 ]

2 and 7 will be cancel now,

→ 149 * 3

→ Rs.447

Hence, Cost of 10(1/2) Litre Petrol is Rs.447.

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Question 8)

→ 1/9 of 1/6 of 1/3

Meaning of "OF" in Maths is Multiple.

So,

→ (1/9) * (1/6) * (1/3)

→ 1/(9*6*3)

→ 1/(9*18)

→ (1/162) (Ans).

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Question 9)

• Length of Photograph = 14(2/5) cm = (72/5) cm.
• Breadth = 10(2/5) cm = (52/5) cm.

So,

→ Required Area (As in Rectangle Shape) = Length * Breadth = (72/5) * (52/5) = (3744/25) cm² = 149(19/25)cm².

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Question 10)

→ Cost of a Burger = Rs.20(3/4) = (83/4) .

→ Cost of 4 Burgers = 4 * Cost of a burger = 4 * (83/4) = Rs.83.

Hence, Cost of 4 such Burgers will be Rs.83.

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Answer 2

Step-by-step explanation:

Q7 cost of 1 litre petrol =rupee 42-4/7

cost of 10-1/2 litre petrol =10-1/2×42-4/7

42-4/7=298/7

10-1/2=21/2

298/7×21/2=5258/14.

so,10-1/2 litre petrol =rupee 5258/14.

Q8 1/9×1/6×1/3=1/162

Q9 length 14-2/5

breath 10-2/5

14-2/5=72/5

10-2/5=52/5

area =72/5×52/5=3744/25

so,area =3744/25

Q10 1 burger=20-3/4=83/4

4 burger =4×83/4=83

so,4 burger =rupee 83