please help me i will mark111111
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your answer hope it's helpful to you dry for bad writing
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BrunoJai:
how can u write cube root of 0.008 as 0
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firstly convert the decimal 0.000729 to normal
i.e 729x10^-6
since in the given question this number is under square so
square root 729x10^-6= 27x10^-3
this bolded number is again under cube root
so cube root 27 x 10^-3=3x10^-1=3/10 ------------ let this be 1
now let us solve the next expression i.ecube root 0.008
we can write 0.008 as 8x10^-3
so cube root of 8x10^-3=2x10^-1=2/10------------ let this be 2
the above question says to add 1 and 2 i.e do 1+2
i.e 3/10+2/10= 5/10= 1/2 =0.5 is the answer
hope u understood
i.e 729x10^-6
since in the given question this number is under square so
square root 729x10^-6= 27x10^-3
this bolded number is again under cube root
so cube root 27 x 10^-3=3x10^-1=3/10 ------------ let this be 1
now let us solve the next expression i.ecube root 0.008
we can write 0.008 as 8x10^-3
so cube root of 8x10^-3=2x10^-1=2/10------------ let this be 2
the above question says to add 1 and 2 i.e do 1+2
i.e 3/10+2/10= 5/10= 1/2 =0.5 is the answer
hope u understood
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