Question

please help me I will surely mark u as brainlist

Answer 1

1 has always denominafor 1
negative power is always comes as positive in denominator

Answer 2

Answer:

1

Step-by-step explanation:

$Given:\frac{1}{1+x^{c-a}+x^{b-a}}+\frac{1}{x^{a-b}+x^{c-b}}+\frac{1}{1+x^{a-c}+x^{b-c}}}$

$=\frac{1}{1+\frac{x^c}{x^a}+\frac{x^b}{x^a}}+\frac{1}{1+\frac{x^a}{x^b}+\frac{x^c}{x^b}}+\frac{1}{1+\frac{x^a}{x^c}+\frac{x^b}{x^c}}}$

$=\frac{x^a}{x^a + x^c + x^b} + \frac{x^b}{x^b + x^a + x^c} + \frac{x^c}{x^c + x^a + x^b}$

$=\frac{x^a + x^b + x^c}{x^a + x^b + x^c}$

$=1$

Hope it helps!