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if alpha and beta are the roots of equation px²-mx+n=0, find the equation whose roots are alpha/beta and beta/alpha
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Answer:
The equation is
px2+qx+r=0
x2+qpx+rp=0
If α and β are the roots, then
the sum of the roots is α+β=−qp
and
the product of the roots is αβ=rp
=α2+β2=(α+β)2−2αβ=q2p2−2rp
The new roots are
(2α+1α) and (2β+1β)
Therefore, the sum of the roots is
(2α+1α)+(2β+1β)
=2(α+β)+(1α+1β)
=2(α+β)+α+βαβ
=(α+β)(2+
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