Question

Please help me....
If one of the zero of the polynomial
ax² - 3(a - 1)x - 1 is 1, then the value of a is ———–———
(i)1 (ii)-1 (iii)2 (iv)-2

Answer 1

Answer:

ax^2-3(a-1)x-1=o X=1

Step-by-step explanation:

=[ax^2-3ax+3x-1]=0

=[a(1)^2-3a(1)+3(1)-1]=0

=[a-3a+3-1]=0

=[-2a+2]=0

=[a=1]

Answer 2

Answer:

Given p(x)= ax² -3(a-1)x -1

p(1)= a(1)² -3(a-1)×1 -1

=> a -3a +3 -1=0

=> -2a +2=0

=> -2a = -2

=> a = 1

So the correct answer is option ¡