Question

please help me if you answer I will mark as brainlist pla​

Answer 1

we can add one to each to power in the prime factorization of an integer, then multiply all the (power + 1)s together. For 540, we would have (2 + 1)(3 + 1)(1 + 1) = 24 factors. To find the number of odd factors (which includes 1), we can exclude any power of 2 and do the same.

Answer 2

Step-by-step explanation:

Numbers with only 3 factors is 4

Numbers with 4 factors are 6

Numbers with 6 factors are 12