Question

please help me if your are maths intelligent​

Answer 1

Answer:

Q1

(i)

$\frac{27x^{2}}{9x} \\= 3x$

(ii)

$\frac{14m^{2}n^{2} }{7mn} \\= 2mn$

(iii)

$\frac{15a^{4}b^{3}}{12a^{2}b}\\ = \frac{5}{4}a^{2}b^{2}$

(iv)

$\frac{48m^{2}n}{-12mn^{2}}\\ = 4mn^{-1}$

(v)

$\frac{-76a^{2}b^{3}c}{-19abc}\\= 4ab^{2}$

Q2

(i)

$\frac{3a^{3}}{a^{2}}\\= 3a$

(ii)

$\frac{4x^{2}y^{2}z^{3}}{xy^{2}z^{2}}\\ = 4xz$

(iii)

$\frac{12p^{6}q^{6}r^{6}}{-3p^{4}q^{2}r}\\ = -4p^{2}q^{4}r^{5}$

(iv)

$\frac{-x^{5}z^{9}}{-xz^{3}}\\ = x^{4}z^{6}$

(v)

$\frac{15a^{5}b^{7}c^{4}}{5a^{2}b^{2}c^{2}}\\ = 3a^{3}b^{5}c^{2}$

Q3

(i)

$\frac{m^{2}-2mn}{m}\\ = \frac{m(m-2n)}{m}\\= (m-2n)$

(ii)

$\frac{z^{3}-3z^{2}+z}{z}\\ = \frac{z(z^{2}-3z+1)}{z}\\ = z^{2}-3z+1$

(iii)

$\frac{k^{6}-7k^{5}+4k^{4}}{k^{2}}\\= \frac{k^{4}(k^{2}-7k+4)}{k^{2}}\\= k^{2}(k^{2}-7k+4)$

(iv)

$\frac{10y^7-8y^6+3y^4}{y^3}\\ = \frac{y^4(10y^3-8y^2+3)}{y^3}\\ = y(10y^3-8y^2+3)$

(v)

$\frac{15u^5-25u^4}{-5u^3}\\ = \frac{5u^4(3u-5)}{-5u^3}\\ =-5u(3u-5)$

Hope it helps...