Question

please help me in both it's urgent....​

Answer 1

Let the original sum of money be y.

He lost 75% of y,

$\sf \: \frac{75}{100} \: \times \: y\: = \: 0.75y$

The second time he lost 75% of the remaining sum.

$\sf \: \frac{75}{100} \: (y - 0.75y) \: = \: 0.75(0.25y)$

After second gambling, the amount remaining is equal to

$\sf \: y - 0.75y - 0.75 \times 0.25y \: = \: 0.0625y$

The third time again, 75% of the remaining after second gambling.

$\sf \: \frac{75}{100} \: \times \: (0.0625y) \: = \: 0.0469y$

The remaining amount is equal to 2.

$\sf \: 0.0625y \: - \: 0.0469 \: = \: 2 \\ \\ \sf \: 0.0156y \: = \: 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \: y \: = \: 128.21 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

The total amount that he had, in the beginning, is equal to Rs. 128.21.