Math, asked by lp5007602, 3 months ago

please help me in maths​

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Answered by Anonymous
1

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Answered by Flaunt
188

\sf\huge\bold{Solution}

\sf \longmapsto\bigg[\dfrac{27}{8}  -  \dfrac{3}{2}  -\bigg ( -  \dfrac{5}{11} \bigg)\bigg]

\sf \longmapsto \dfrac{27}{8}  -  \dfrac{3}{2}  +  \dfrac{5}{11}

=>>LCM of 8,2 & 11 is 88

\sf \longmapsto \dfrac{27 \times 11 - 3 \times 44 + 5 \times 8}{88}

\sf \longmapsto \dfrac{297 - 132 + 40}{88}

\sf \longmapsto \dfrac{165 + 40}{88}  =  \dfrac{205}{88}

Solving second question:

\sf \longmapsto\bigg( \dfrac{1}{2}  \times  \dfrac{8}{3}\bigg ) + \bigg[\dfrac{4}{5}  \times  -  \dfrac{25}{3} \bigg]

\sf \longmapsto \dfrac{8}{6}  + \bigg[ \dfrac{4}{5}   \times  -  \dfrac{25}{3} \bigg]

\sf \longmapsto \dfrac{8}{6}  + \bigg[-  \dfrac{100}{15} \bigg]

\sf \longmapsto \dfrac{8}{6}  -  \dfrac{20}{3}  =  \dfrac{8 - 40}{6}  =  -  \dfrac{32}{6}  =  -  \dfrac{16}{3}

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