Question

please help me in solving both sums​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

b tan theeta =a

Tan theeta =a/b

Tan theeta =P/B

Therefore

P/B=a/b

Perpendicular =a and Base =b

So hypotenious is ( root a=b) use pythagorian theorm

Cos theeta =B/H =b/(root a+b)

Sin theeta =P/H = a/( root a+b)

Now put the value of sin theeta and coss theeta in the question