Please help me in solving this.
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EA || BD
so, AB is transversal
so, /_ EAB=/_DBA (alternate angles)
so, 2x=2y
so, x=y
so, /_FAB=/_CBA
Considering AB as tranversal
we get AF || BC
so, AB is transversal
so, /_ EAB=/_DBA (alternate angles)
so, 2x=2y
so, x=y
so, /_FAB=/_CBA
Considering AB as tranversal
we get AF || BC
srishapoddar:
thanks a ton, mate!
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