Question

please help me in solving this

Answer 1

${x}^{2} - 5x + 4 = 0 \\ {x}^{2} - 4x - x + 4 = 0 \\ x(x - 4) - 1(x - 4) = 0 \\ (x - 4)(x - 1) = 0 \\ therefore. x - 1 = 0 \\ x = 1 \\ x - 4 = 0 \\ x = 4$
Hope it's helpful

Answer 2

x2 - 5x + 4 =0

x2 - 4x - x + 4 = 0

x(x - 4) - 1(x -4) = 0

(x - 4) (x - 1) =0

if x - 4 =0

then x = 4

if x- 1 =0

then x = 1