Please help me in solving this question
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As AB=AC(Given)
So angel ABC =angel ACB(angels opposite to equal sides are equal)
Thus this makes PB=QC(as they are opposite to equal angels which make them equal)
HOPE THIS HELPS:)
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Given : AP=AQ
AB=AC
To Prove : PB=QC
Proof : In ∆APB & ∆AQC
AP = AQ {given}
AB = AC {given}
angle PAB = angle QAC {V.O.A}
∆APB=~∆AQC (S.A.S)
PB = QC {C.P.C.T}
AB=AC
To Prove : PB=QC
Proof : In ∆APB & ∆AQC
AP = AQ {given}
AB = AC {given}
angle PAB = angle QAC {V.O.A}
∆APB=~∆AQC (S.A.S)
PB = QC {C.P.C.T}
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