please help me in solving this question.iwill Mark you as brainlest and follow
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Sec 3A = Cosec( A - 20)
Sec 3A = Sec ( 90 - (A - 20)).
Using [CosecA = Sec(90 - A]
3A = 90 - ( A - 20)
3A = 90 - A + 20
3A + A = 110
4A = 110
A = 110/4 = 27.5
Ans. A = 27.5
Sec 3A = Sec ( 90 - (A - 20)).
Using [CosecA = Sec(90 - A]
3A = 90 - ( A - 20)
3A = 90 - A + 20
3A + A = 110
4A = 110
A = 110/4 = 27.5
Ans. A = 27.5
SakshaM725:
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N O
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sec 3A=cosec(A-20),
sec3A=sec(90-(A-20)),
sec3A=sec(90-A+20),
sec3A=sec(110-A),
on comparing,
3A=110-A,
3A+A=110,
4A=110,
A=110/4A=27.5,
hope this helps u
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