Math, asked by ramasaraysingh9, 3 months ago

please help me in solving this two question

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Answers

Answered by ahelily

1

Step-by-step explanation:

in tri.acm nd tri. bcm

am = bm ( cm, midpoint of am)

ang.a = ang.b (given)

cm common side

tri.acm congruent to tri.bcm (aas congruency)

angl.cma = angl.cmb ( cpct)

both the angls. are on same line

therefore, cma =90°

cm perpendicular to ab (proven)

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