please help me in solving this two question
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Step-by-step explanation:
in tri.acm nd tri. bcm
am = bm ( cm, midpoint of am)
ang.a = ang.b (given)
cm common side
tri.acm congruent to tri.bcm (aas congruency)
angl.cma = angl.cmb ( cpct)
both the angls. are on same line
therefore, cma =90°
cm perpendicular to ab (proven)
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