Physics, asked by suhanidhanuka2020, 1 month ago

Please help me in the answer

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Answered by NewGeneEinstein
1

Solution:-1

  • Displacements=2m,4m
  • Times=2s,4s

\boxed{\sf Average\;Velocity=\dfrac{Total\:displacement}{Total\:Time}}

\\ \sf\longmapsto Average\:velocity=\dfrac{2+4}{2+4}

\\ \sf\longmapsto Average\:Velocity=\dfrac{6}{6}

\\ \sf\longmapsto Average\:velocity=1m/s

Solution:-2

  • Displacement=4

As its unchanged velocity=0

Solution:-3.

  • Times=2s,2s,2s
  • Displacement =4m,2m

\\ \sf\longmapsto Average\;Velocity=\dfrac{4+2}{2+2+2}

\\ \sf\longmapsto Average\:Velocity=\dfrac{6}{6}

\\ \sf\longmapsto Average\:Velocity=1m/s

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