Question

PLEASE !!!!

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HELP ME IN THE FOLLOWING QUESTION WHICH ARE ATTACHED ABOVE! ⤴⤴⤴⤴


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NO SPAM REQUIRED ❎❎

✔ ✔ONLY EXPERTS REQUIRED ✔✔​

Answer 1

$heya \\ \\ 1) \\ \\ 2 {}^{2x} - 2 {}^{x + 3} + 2 {}^{4} = 0 \\ \\ 2 {}^{x} \times 2 {}^{x} - 8 \times 2 {}^{x} + 16 = 0 \\ \\ put \: 2 {}^{x} = y \\ \\ y {}^{2} - 8y + 16 = 0 \\ \\ y {}^{2} - 4y - 4y + 16 = 0 \\ \\ y(y - 4) - 4(y - 4) = 0 \\ \\ y = 4 \\ \\ so \: \: \: \: 2 {}^{x} = 4 \\ \\ 2 {}^{x} = 2 {}^{2} \\ \\ x = 2 \\ \\ \\ \\ \ \\ 2) \\ \\ \\ 3 {}^{2x + 4} + 1 = 2 \times 3 {}^{x + 2} \\ \\ 3 {}^{2x + 4 - x - 2} + 3 {}^{ - x - 2} = 2 \\ \\ 3 {}^{x + 2} + 3 {}^{ - x - 2} = 2 \\ \\ 81 \times 3 {}^{x} + 3 {}^{ - x} = 18 \\ \\ \\ \\ put \: \: \: \: \: 3 {}^{ x} = \alpha \\ \\ 81 \alpha {}^{2} - 18 \alpha + 1 = 0 \\ \\ 81 \alpha {}^{2} - 9\alpha - 9 \alpha + 1 = 0 \\ \\ 9 \alpha (9 \alpha - 1) - 1(9 \alpha - 1) = 0 \\ \\ (9 \alpha - 1) = 0 \\ \\ \alpha = 3 {}^{ - 2} \\ \\ \\ so \: \: \: 3 {}^{x} = 3 {}^{ - 2} \\ \\ \\ x = - 2$

Answer 2

The second solution being easy is done first, and the first solution being tricky done at the end.

Nothing hard is there on the solutions. You can see them and I am sure, you will catch them at once.

Keep going with various kinds of books, test papers, etc., and you will feel your stage of success. A poor student also can get develop by rapif self study like this way.

The only thing in these kinds of numericals is that, how can you make easy the given question. It may occur, one numerical is getting solved in various ways by different students. Some are shortly solved whereas some are lengthy (time-consuming). We should accept the shorter ones since one fact during exam time, "Time less, Question large".