Question

please help me in these question​

Answer 1

Step-by-step explanation:

given = AB perpendicular OP

x:y:z= 1:3:5

let,

x= 1a

y=3a

z=5a

1a+3a+5a=90

9a=90

a=10

therefore

x= 1a=10°

y= 3a=30°

z= 5a =50°

Answer 2

since, PO is perpendicular to ab, so angle AOP = ANGLE POB = 90° .....(i)

now, ratio of x:y:z = 1:3:5

let the common multiple be x

so, x = 1x, y = 3x, z = 5x. .....(ii)

now, angle POA + angle POB = 180° [linear pair]

x + y + z + angle POB = 180°

x + 3x +5x + 90° = 180° [using (i) and (ii)]

9x + 90° = 180°

9x = 90°

x = 10° [ 90/9 = 10]

so , x = 10°

now, y = 3x = 3 * 10 = 30° [using (ii)]

hence, y = 30°

also, z = 5x = 5 * 10 = 50° [using (ii)]

therefore, z = 50°

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