Math, asked by kr8822670, 1 day ago

Please help me in this 2 questions

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Answered by alokkumar3324
0

Answer:

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The sum of first 16 terms of the A.P. 10,6,2,... is

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Solution

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Correct option is A)

Hint:- The sum formula for n terms of an A.P. (

2

n

{2a+(n−1)d}) will be used along with the related terms.

Given:-

Sequence: 10,6,2,...

a=10=first term

n=16=no. of terms

Step 1: Finding the common difference 'd' of the given sequence 10,6,2,....

second term − first term =a

2

−a

1

=6−10=−4

third term − second term =a

3

−a

2

=2−6=−4

As the difference is same in all the cases, hence it's common difference=d=−4

Step 2: Finding the sum of the first 16 terms by replacing the given terms in the sum formula of A.P.

S

n

=

2

n

{2a+(n−1)d}

So replacing the required terms in the formula we will get,

S

16

=

2

16

{2×10+(16−1)d}

=

2

16

{20+15×(−4)}

=

2

16

(20−60)

=8(−40)

=8×(−40)

=−320

Hence, the sum of the first 16 terms would be −320

Final Step: Hence, the sum of the first 16 terms would be −320

Step-by-step explanation:

mark my answer brainliest pls

Answered by rachanasrivastava922
0

Step-by-step explanation:

In ques 1 for finding discriminant of the eq use D= b square - 4 ac and with this only u can also find the nature of roots by the value of d , is greater or smaller or equal ....

In ques 2 for finding 16th term use the formula An= a + ( n - 1 ) * d...with this you will get your 16th term...

hope it helped ...✌️

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