Question

please help me in this

Answer 1

Given

V=50cm
M=1

Image formed by the len is real and inverted so
M=u/v

1=u/v

U=v

U=-50cm


Distance of object =50cm

Using lens formula

I/f=1/v-1/u

$\frac{1}{f} = \frac{1}{50} - \frac{1}{ - 50}$
$\frac{1}{f } = \frac{1 + 1}{50}$

$\frac{1}{f} = \frac{2}{50}$

$\frac{1}{f} = \frac{1}{25}$

F=25cm

Changing in meter

F=. 25m


Power of lens = 1/f

P= 1/.25 =100/25 =4

Power of lens is +4 D

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