Question

please help me in this answer....
screanshot below

Answer 1

Answer:

(I) angle ECD + angle ACE barabar 180 degree {by linear pair} = 35°+ACE = 180°. = ACE = 180°-35° = 145°.

(ii) angle ACB = angle ACE + angle ECD =angle angle ACB = 145°- 35° = ACB = 120°.

(iii) in triangle abc

angle BAC + angle CBC + angle BAC =180° { by angle sum property} so angle abc =30°