Question

please help me in this maths question help me​

Answer 1

Given:-

• $\dfrac{a}{b} =\dfrac{5}{3}$

Solution:-

The correct method is as follows.

Let $a=5k$ and $b=3k$.

$\therefore\dfrac{a+7b}{7b} =\dfrac{5k+21k}{21k} =\dfrac{26\cancel{k}}{21\cancel{k}} =\dfrac{26}{21}$

According to your question,

$\dfrac{a}{b} =\dfrac{5}{3}$

Now we divide by 7 on both sides.

$\therefore \dfrac{a}{7b} =\dfrac{5}{21}$

Then we add one on both sides.

$\therefore \dfrac{a+7b}{7b} =\dfrac{5+21}{21}=\dfrac{26}{21}$

Answer 2

To Find:-

• $\sf \: Find \: the \: ratio \: of \: \: \dfrac { a + 7b } { 7b }$

Solution:-

Given ,

• $\sf \: \dfrac { a } { b } = \dfrac { 5 } { 3 }$

a = 5k , b = 3k

Substitute:-

$\longrightarrow\sf \: \dfrac { 5k + 7( 3k ) } { 7( 3k ) }$

$\longrightarrow\sf \: \dfrac { 5k + 21k } { 21k }$

$\longrightarrow\sf \: \dfrac { 26k } { 21k }$

$\longrightarrow\sf \: \dfrac { 26 } { 21 }$

Hence ,

• Value of $\sf \: \dfrac { a + 7b } { 7b } = \dfrac { 26 } { 21 }$