Please help me in this maths question. Thanks
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the answer is in the above attachment
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We see that the line containing the origin and the point of least argument p in B forms a tangent to the circle |z−u|=1. The segment of this line between the two points has length 22–√ and is the hypotenuse of a right triangle with one leg of length 1 (corresponding to the circle's radius). Therefore the length of the other leg, which is also the modulus of p and the answer to the question, is
(22–√)2−12−−−−−−−−−−√=7
With notation of z=x+iy
You have to solve the equation of
|z-(2-2i)|^2\leq 4 for Re(z)=x
(Re(z)-2)^2+(Im(z)+2)^2\leq 4
From this
Re(z)\leq\sqrt{4-(Im(z))^2}+2
For maximum Im(z)=y=0
So you will get the maximum value of Re(z)
You can read down it from your sketch, too
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